Exercise 3.1 Page: 44 1.Aftab tells his daughter, “Seven years ago, I was seven times as old as you were then. Also, three yearsfrom now, I shall be three times as old as you will be.” (Isn’t this interesting?) Represent this situationalgebraically and graphically.Solutions:Let the present age of Aftab be ‘x’. And, the present age of his daughter be ‘y’. Now, we can write, seven years ago, Age of Aftab = x – 7 Age of his daughter = y – 7 According to the question, x−7 = 7(y−7) ⇒x−7 = 7y−49⇒x−7y = −42 ………………………(i) Also, three years from now or after three years, Age of Aftab will become = x + 3. Age of his daughter will become = y + 3 According to the situation given, x+3 = 3(y+3) ⇒x+3 = 3y+9⇒x−3y = 6 …………..…………………(ii) Subtracting equation (i) from equation (ii) we have (x−3y)−(x−7y) = 6−(−42) ⇒−3y+7y=6+42⇒4y=48⇒y=12The algebraic equation is represented by x−7y = −42 x−3y = 6 For, x−7y =−42 or x = −42+7y The solution table is For, x−3y=6 or x=6+3y The solution table is